My answer will eventually appear in the comments, but you're free to take a stab at the problem and provide your own answer. Show your work! Note to SAT students: this might be a GRE problem, but it isn't so different from the sort of problem you might see on the SAT I. Feel free to join in.
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1 comment:
This looks like a "systems of equations" problem, so let's set up the two equations:
Calories for both types of snacks have to total up to 3250, so:
Let A = # of servings of Snack A
Let B = # of servings of Snack B
200A + 350B = 3250, or
20A + 35B = 325, or
4A + 7B = 65
We also need to create an equation that reckons the cost which, for the purchasing of both types of snack, totals $11.
1.7A + .6B = 11, or
17A + 6B = 110
Let's pair these equations up:
4A + 7B = 65
17A + 6B = 110
Let's get rid of the B by multiplying each equation by a factor that gives us 42B in each case:
6(4A + 7B = 65)
7(17A + 6B = 110)
which gives us:
24A + 42B = 390
119A + 42B = 770
Switch and subtract:
[119A + 42B = 770]
-[24A + 42B = 390]
___________________
95A = 380
A = 4
We can stop here. The correct answer would appear to be (C): the two quantities are equal.
QED. (Or is it?)
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